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Free USMLE Step 1 Reproductive and Endocrine practice questions
10 original exam-style questions from the StepStash Step 1 qbank, each with a full explanation, an educational objective and a link to the matching study note. Try each one before you open the answer. Reviewed by Veli Bakalov, MD · @HemeOncBuddy.
A 47-year-old woman comes to the physician because of episodes of pounding headache, palpitations, and sweating over the past 6 months. Blood pressure is 176/102 mm Hg. Plasma free metanephrines and normetanephrines are markedly elevated, and CT shows a 5-cm left adrenal mass. Phenoxybenzamine is started. Because her tumor is large and her blood pressure remains difficult to control, metyrosine is added before adrenalectomy. Two weeks later she reports drowsiness.
Metyrosine most likely inhibits which of the following enzymes?
Tyrosine hydroxylase
Aromatic L-amino acid (DOPA) decarboxylase
Dopamine β-hydroxylase
Phenylethanolamine N-methyltransferase
Catechol-O-methyltransferase
Show answer and explanation
Correct answer: A. Tyrosine hydroxylase
Episodic headache, palpitations, and sweating with elevated plasma metanephrines and an adrenal mass indicate a pheochromocytoma. Catecholamine synthesis proceeds tyrosine to L-DOPA (tyrosine hydroxylase, BH4 cofactor), L-DOPA to dopamine (DOPA decarboxylase, pyridoxal phosphate), dopamine to norepinephrine inside the vesicle (dopamine β-hydroxylase, copper and vitamin C), and norepinephrine to epinephrine in chromaffin cells (PNMT, induced by cortisol). Tyrosine hydroxylase is the rate-limiting step, and metyrosine (α-methyl-p-tyrosine) is a competitive inhibitor of it, lowering production of all downstream catecholamines. It is added to α-blockade (always started before any β-blocker) in large or poorly controlled tumors before surgery, or for inoperable disease. Because it also reduces central catecholamine synthesis, sedation is its most common adverse effect; crystalluria and extrapyramidal symptoms can also occur.
B. DOPA decarboxylase is inhibited peripherally by carbidopa, used with levodopa in Parkinson disease, not in pheochromocytoma. C. Dopamine β-hydroxylase acts inside vesicles; its inhibition would lower norepinephrine but raise dopamine and is not the target of metyrosine. D. PNMT converts norepinephrine to epinephrine; inhibiting it would not reduce norepinephrine output. E. COMT inhibition (entacapone) would decrease metanephrine formation and raise catecholamine levels, worsening hypertension.
Educational objective: The key takeaway is that metyrosine inhibits tyrosine hydroxylase, the rate-limiting enzyme of catecholamine synthesis, and is used with α-blockade to prepare patients with pheochromocytoma for surgery.
Metyrosine, reserpine, guanethidine, bretylium and clonidine lower NE output; MAO inhibitors, amphetamine, ephedrine, tyramine and NET blockers raise synaptic NE.
A 61-year-old man with alcohol-associated cirrhosis is seen for follow-up of ascites. He has no tingling, cramps or muscle spasms. Chvostek and Trousseau signs are negative, and the ECG shows a normal QT interval. Laboratory studies show total serum calcium 7.4 mg/dL (8.4 to 10.2), albumin 2.0 g/dL (3.5 to 5.0), phosphate 3.4 mg/dL, magnesium 1.9 mg/dL and arterial pH 7.41. PTH is 38 pg/mL (10 to 65).
Which of the following is the best estimate of his serum calcium corrected for albumin?
7.4 mg/dL
8.2 mg/dL
9.0 mg/dL
9.8 mg/dL
10.6 mg/dL
Show answer and explanation
Correct answer: C. 9.0 mg/dL
About 40% of serum calcium is bound to proteins, mainly albumin, about 10% is complexed with anions such as phosphate and citrate, and about 50% is free ionized calcium, the only physiologically active fraction and the one that PTH senses and regulates. When albumin falls, as in cirrhosis, nephrotic syndrome or malnutrition, the protein-bound fraction shrinks and total calcium falls, but ionized calcium stays normal because PTH continues to defend it. This is pseudohypocalcemia, and it fits his absence of symptoms, negative Chvostek and Trousseau signs, normal QT and normal PTH.
The usual estimate is: corrected calcium = measured calcium + 0.8 × (4 minus albumin in g/dL). Here, 7.4 + 0.8 × (4 minus 2.0) = 7.4 + 1.6 = 9.0 mg/dL, which is normal. The formula is only an approximation, and when albumin or pH is abnormal, or in critical illness, ionized calcium should be measured directly.
A. 7.4 mg/dL is the uncorrected measured value and overstates the problem. B. 8.2 mg/dL results from adding 0.8 only once (or from using 0.4 per g/dL), underestimating the correction. D. 9.8 mg/dL would require a correction factor of 1.2 per g/dL. E. 10.6 mg/dL results from adding 0.8 for each 0.5 g/dL rather than for each 1 g/dL of albumin below 4.
Educational objective: The key takeaway is that hypoalbuminemia lowers total but not ionized calcium, and corrected calcium = measured calcium + 0.8 × (4 minus albumin).
Only ionized calcium is active: low albumin lowers the total but not the ionized level, while alkalosis and citrate lower ionized calcium even though the total looks normal.
A 15-day-old boy is brought to the emergency department because of 3 days of poor feeding, repeated vomiting and decreasing wet diapers. He was born at term and his newborn examination was normal; newborn screening results are pending. He is lethargic, with a heart rate of 188/min and blood pressure of 58/30 mm Hg. Mucous membranes are dry, and the scrotal skin and areolae are darkly pigmented. External genitalia are normal male with descended testes. Fingerstick glucose is 42 mg/dL.
Which of the following sets of laboratory findings is most likely in this patient?
Sodium low, potassium high, plasma renin activity high
Correct answer: A. Sodium low, potassium high, plasma renin activity high
A boy who looks normal at birth and then, at 1 to 3 weeks of age, develops vomiting, dehydration, hypotension, hypoglycemia and genital hyperpigmentation has salt-wasting 21-hydroxylase deficiency. Boys are not detected at birth because they have no genital ambiguity, so they present with this adrenal crisis.
Loss of CYP21A2 blocks both branches that need 21-hydroxylation: progesterone cannot become 11-deoxycorticosterone on the way to aldosterone, and 17-hydroxyprogesterone cannot become 11-deoxycortisol on the way to cortisol. Without aldosterone, principal cells of the collecting duct reabsorb less sodium through ENaC and secrete less potassium and hydrogen ion, giving hyponatremia, hyperkalemia and a mild metabolic acidosis. The resulting volume depletion lowers renal perfusion pressure and strongly stimulates the juxtaglomerular cells, so plasma renin activity is high. Cortisol deficiency adds hypoglycemia and hypotension, and the high ACTH (from loss of feedback) stimulates melanocortin-1 receptors, causing hyperpigmentation.
B. Low sodium and high potassium with low renin is hyporeninemic hypoaldosteronism (type 4 renal tubular acidosis), which is driven by low renin rather than by volume depletion. C. High sodium, low potassium and low renin reflect mineralocorticoid excess, as in 11β-hydroxylase deficiency or apparent mineralocorticoid excess, which cause hypertension. D. Hypokalemia with high renin is the pattern of pyloric stenosis, in which vomiting of gastric acid causes hypochloremic, hypokalemic metabolic alkalosis with secondary hyperaldosteronism; it presents somewhat later and without hyperpigmentation or hyperkalemia. E. Hyponatremia with low renin and normal potassium suggests SIADH, a volume-expanded state.
Educational objective: The key takeaway is that salt-wasting 21-hydroxylase deficiency causes hyponatremia, hyperkalemia and high renin at 1 to 3 weeks of age, and boys present this way because their genitalia are normal.
Cortisol needs 17α-, 21- and 11β-hydroxylation; aldosterone skips 17α and androgens exit at 17,20-lyase. Ketoconazole blocks the first step, metyrapone-type drugs block 11β-hydroxylase, and abiraterone blocks CYP17.
A 58-year-old man is brought to the emergency department 2 hours after the abrupt onset of the worst headache of his life, followed by vomiting and double vision. He began apixaban for atrial fibrillation 3 weeks ago. Pulse is 118/min and blood pressure is 82/50 mm Hg despite 2 L of intravenous saline. He has a right ptosis with a dilated, poorly reactive right pupil and a bitemporal visual field defect. Serum sodium is 128 mEq/L, potassium is 4.3 mEq/L, and glucose is 61 mg/dL. MRI shows a 2.5-cm sellar mass containing fresh hemorrhage.
Deficiency of which of the following hormones is most responsible for this patient's hypotension?
Aldosterone
Cortisol
Thyroxine
Antidiuretic hormone
Growth hormone
Show answer and explanation
Correct answer: B. Cortisol
This patient has pituitary apoplexy: sudden hemorrhage into a previously unrecognized macroadenoma, here precipitated by anticoagulation. The thunderclap headache, vomiting, oculomotor palsy from lateral expansion into the cavernous sinus and bitemporal hemianopia from chiasmal compression all reflect abrupt expansion of the sellar contents.
The life-threatening feature is acute ACTH deficiency. Without ACTH, the adrenal fasciculata stops producing cortisol within hours. Cortisol is needed for vascular responsiveness to catecholamines (it upregulates alpha-1 adrenergic receptors and supports vascular tone), so its loss causes vasodilatory shock that resists fluids alone. Cortisol deficiency also explains the hypoglycemia (loss of gluconeogenic support) and contributes to hyponatremia, because cortisol normally suppresses ADH release, so free water is retained. This is why stress-dose hydrocortisone is given first, before imaging-driven decompression and before any thyroid hormone.
A. Aldosterone is wrong because its secretion is driven mainly by angiotensin II and potassium, which still work in secondary (pituitary) adrenal insufficiency; the normal potassium here confirms that the zona glomerulosa is intact.
C. Thyroxine deficiency develops over weeks because T4 has a half-life of about 7 days, and replacing it before cortisol can precipitate adrenal crisis.
D. ADH deficiency would cause diabetes insipidus with hypernatremia, not hyponatremia, and is rare with adenomas because ADH is made in the hypothalamus.
E. Growth hormone loss is common in hypopituitarism but does not cause acute shock.
Educational objective: The key takeaway is that pituitary apoplexy causes shock through acute ACTH and cortisol deficiency, while aldosterone is preserved because the renin-angiotensin system remains intact.
A macroadenoma presses up on the chiasm (bitemporal hemianopia), sideways into the cavernous sinus (III, IV, V1, V2, VI), on the stalk (modest prolactin rise) and on the gland itself (GH and gonadotropins lost first).
A 27-year-old woman with type 1 diabetes mellitus mistakenly injects her prandial insulin dose twice before dinner. Thirty minutes later, she develops tremor, palpitations, hunger and anxiety. Pulse is 118/min, and blood pressure is 146/70 mm Hg. Fingerstick glucose is 42 mg/dL. Plasma epinephrine measured at this time is more than 10 times her baseline value. She recovers after drinking orange juice.
The increase in this patient's plasma epinephrine is triggered by release of which of the following neurotransmitters onto which receptor type on adrenal chromaffin cells?
Norepinephrine onto α1 receptors
Acetylcholine onto Nn nicotinic receptors
Acetylcholine onto M3 muscarinic receptors
Norepinephrine onto β1 receptors
Acetylcholine onto Nm nicotinic receptors
Show answer and explanation
Correct answer: B. Acetylcholine onto Nn nicotinic receptors
Hypoglycemia is sensed by glucose-responsive neurons in the hypothalamus and brainstem, which drive a sympathoadrenal discharge. The resulting surge of circulating epinephrine raises glucose (hepatic glycogenolysis and gluconeogenesis) and produces the adrenergic warning symptoms seen here: tremor, palpitations, anxiety and a widened pulse pressure from β1 and β2 effects.
The adrenal medulla is one of the two exceptions to the usual sympathetic wiring. It receives preganglionic fibers from the thoracic splanchnic nerves directly, with no intervening ganglion. Like every preganglionic autonomic neuron, these fibers release acetylcholine onto Nn (neuronal) nicotinic receptors, ligand-gated cation channels. Opening of these channels depolarizes the chromaffin cells, which are neural crest derived, modified postganglionic sympathetic neurons. Calcium entry then triggers exocytosis of granules containing mostly epinephrine (made from norepinephrine by cortisol-induced PNMT). This is why ganglionic blockers such as mecamylamine blunt adrenal epinephrine release.
A and D are wrong because norepinephrine is released by most sympathetic postganglionic fibers onto target organs, not by the fibers that innervate the adrenal medulla, and chromaffin cells are not activated through adrenergic receptors. C is wrong because muscarinic receptors are the targets of parasympathetic postganglionic fibers and of the other sympathetic exception, the cholinergic fibers to eccrine sweat glands. E is wrong because Nm receptors are the muscle-type nicotinic receptors at the neuromuscular junction of skeletal muscle, the site of action of nondepolarizing blockers such as rocuronium, not the receptors on autonomic ganglion cells or chromaffin cells.
Educational objective: The key takeaway is that the adrenal medulla is innervated directly by sympathetic preganglionic fibers that release acetylcholine onto Nn nicotinic receptors on chromaffin cells, triggering epinephrine secretion.
Every preganglionic synapse is ACh on Nn; sweat glands and the adrenal medulla are the sympathetic exceptions.
A 3-week-old girl is brought to the physician because her head circumference has increased from the 50th to above the 97th percentile since birth. She was born at term after an uneventful pregnancy. The anterior fontanelle is bulging, and funduscopic examination shows bilateral yellow-white retinal scars with pigmented borders. CT of the head shows enlarged lateral ventricles with multiple calcifications scattered throughout the cerebral cortex and white matter. Results of a newborn hearing screen were normal.
Which of the following maternal exposures during pregnancy is the most likely source of this infant's infection?
Unpasteurized soft cheese
Saliva and urine of a toddler in day care
Mosquito bites during travel to the tropics
Undercooked meat containing tissue cysts
Close contact with a child with a facial rash
Show answer and explanation
Correct answer: D. Undercooked meat containing tissue cysts
This infant has the classic triad of congenital toxoplasmosis: hydrocephalus (rapidly growing head, bulging fontanelle, enlarged ventricles), chorioretinitis (pigmented retinal scars) and diffuse intracranial calcifications. The distribution of calcium is the discriminating clue: Toxoplasma scatters calcifications randomly through the parenchyma, whereas CMV deposits them in a periventricular rim and Zika favors the subcortical junction.
Toxoplasma gondii is an obligate intracellular protozoan whose definitive host is the cat. Humans become infected by ingesting tissue cysts (bradyzoites) in undercooked meat such as pork, lamb or venison, or by ingesting oocysts from cat feces in litter, soil or unwashed produce. When a woman acquires a primary infection during pregnancy, tachyzoites disseminate and cross the placenta. Maternal infection is usually silent, so the diagnosis is often made in the infant. Prevention focuses on cooking meat thoroughly, washing produce and having someone else change the cat litter.
A. Unpasteurized soft cheese transmits Listeria monocytogenes, which causes amnionitis, preterm birth and neonatal sepsis or meningitis rather than this triad.
B. Young children in day care shed CMV in saliva and urine; congenital CMV causes periventricular calcifications, microcephaly and sensorineural hearing loss.
C. Aedes mosquitoes transmit Zika virus, which causes severe microcephaly, not hydrocephalus with macrocephaly.
E. A child with a slapped-cheek rash spreads parvovirus B19, which causes fetal anemia and hydrops.
Educational objective: The key takeaway is that congenital toxoplasmosis (hydrocephalus, chorioretinitis, diffuse calcifications) is acquired from tissue cysts in undercooked meat or oocysts in cat feces.
Where the calcium sits separates the congenital calcifiers: diffuse in toxoplasmosis, periventricular in CMV, subcortical in Zika.
Question 7 · Amenorrhea & Hyperandrogenism · medium
A 31-year-old woman comes to the physician because of heavy, prolonged vaginal bleeding after 4 months without a period. She has had irregular menses since menarche and has been unable to conceive for 2 years. BMI is 36 kg/m2. There is coarse hair on the upper lip and chin and velvety hyperpigmented plaques on the posterior neck. Urine beta-hCG is negative. Pelvic ultrasound shows enlarged ovaries with many small peripheral follicles and an endometrial stripe of 18 mm. Endometrial biopsy shows crowded, irregular proliferative glands without cytologic atypia.
Which of the following best explains this patient's endometrial findings?
Direct mitogenic effect of testosterone on endometrial glands
High FSH stimulating endometrial stromal growth
Insulin-mediated increase in progesterone synthesis
Chronic estrogen stimulation without luteal progesterone
Loss of estrogen receptors in the endometrium
Show answer and explanation
Correct answer: D. Chronic estrogen stimulation without luteal progesterone
Oligomenorrhea since menarche, infertility, hirsutism, obesity with acanthosis nigricans and polycystic-appearing ovaries indicate polycystic ovary syndrome. Rapid GnRH pulses favor LH over FSH, so theca cells overproduce androgens, and insulin resistance amplifies theca androgen output and lowers SHBG. The relative FSH deficiency stalls follicle maturation, so ovulation does not occur and no corpus luteum forms. Without a corpus luteum there is no luteal-phase progesterone. Meanwhile estrogen is continuously present, from the ovaries and from aromatization of androgens in adipose tissue. Estrogen drives endometrial proliferation, and progesterone normally converts it to secretory endometrium and then triggers shedding. Unopposed estrogen therefore produces endometrial hyperplasia, irregular heavy breakthrough bleeding and an increased risk of endometrioid endometrial carcinoma. Progestins or combined oral contraceptives protect the endometrium.
A. Androgens are not the main endometrial mitogen; their effect on the endometrium is mainly through aromatization to estrogen.
B. FSH is relatively low in PCOS, and FSH acts on granulosa cells, not on the endometrium.
C. Insulin raises ovarian androgen, not progesterone, production; lack of progesterone is the problem.
E. Estrogen receptors are retained and continuously stimulated; their loss would cause an atrophic endometrium.
Educational objective: The key takeaway is that anovulation in PCOS leaves estrogen unopposed by luteal progesterone, causing endometrial hyperplasia and raising the risk of endometrial carcinoma.
Fast GnRH pulses (LH over FSH) and insulin resistance converge on the theca cell; stalled follicles explain anovulation, and unopposed estrogen explains the endometrial risk.
A 29-year-old woman at 34 weeks' gestation is admitted with preeclampsia with severe features and receives an intravenous magnesium sulfate infusion. Fourteen hours later, her urine output has fallen to 15 mL/h over the past 4 hours. She is now drowsy and flushed. Respiratory rate is 10/min. Patellar and biceps reflexes, brisk on admission, are now absent. Serum magnesium is 9.8 mg/dL (therapeutic range 4.8 to 8.4).
Which of the following mechanisms best explains this patient's loss of deep tendon reflexes?
Competitive blockade of nicotinic receptors at the motor end plate
Inhibition of acetylcholinesterase in the synaptic cleft
Upper motor neuron dysfunction from cerebral vasogenic edema
Reduced calcium-dependent acetylcholine release from motor nerve terminals
Muscle membrane hyperpolarization from hypokalemia
Show answer and explanation
Correct answer: D. Reduced calcium-dependent acetylcholine release from motor nerve terminals
Magnesium sulfate is the drug of choice to prevent and treat eclamptic seizures. Magnesium is cleared by the kidney, so when her urine output fell, the serum level climbed into the toxic range.
Magnesium is a physiologic calcium antagonist. At the neuromuscular junction, it competes with Ca2+ at voltage-gated calcium channels of the presynaptic motor nerve terminal. Acetylcholine release by synaptic vesicle exocytosis depends on that Ca2+ influx, so less acetylcholine is released per impulse and the end-plate potential shrinks. Neuromuscular transmission fails progressively: deep tendon reflexes disappear first (around 9 to 12 mg/dL), then respiratory depression follows, then cardiac conduction block and arrest. This fixed order is why reflexes, respiratory rate and urine output are monitored during the infusion. The treatment is to stop the infusion and give calcium gluconate, which overcomes the competitive antagonism at the nerve terminal.
A. Competitive nicotinic receptor blockade is the mechanism of nondepolarizing neuromuscular blockers such as rocuronium; magnesium acts mainly before the synapse.
B. Acetylcholinesterase inhibition increases acetylcholine and would cause fasciculations and cholinergic signs, not flaccid areflexia.
C. Upper motor neuron dysfunction from cerebral edema causes hyperreflexia, the expected finding in preeclampsia before magnesium; areflexia points away from it.
E. Hypokalemia can cause weakness, but magnesium infusion does not lower potassium enough to explain this, and her serum magnesium is clearly toxic.
Educational objective: The key takeaway is that magnesium blocks presynaptic calcium entry and acetylcholine release at the neuromuscular junction, so toxicity abolishes deep tendon reflexes before causing respiratory depression, and calcium gluconate reverses it.
Magnesium toxicity climbs in a fixed order, and reflexes go first; because magnesium is renally cleared, falling urine output speeds the climb. Stop the infusion and give calcium gluconate.
A 55-year-old woman has an abnormal screening mammogram showing a 2-cm cluster of fine, linear, branching microcalcifications in the left upper outer quadrant. She has no palpable mass, skin change or nipple discharge. Stereotactic core biopsy shows ducts distended by sheets of large, pleomorphic cells with frequent mitoses and a central core of necrotic debris containing calcifications. Immunostaining for p63 shows a continuous ring of myoepithelial cells around every involved duct, and no tumor cells are present in the surrounding stroma.
Which of the following is the most likely diagnosis?
Lobular carcinoma in situ
Invasive ductal carcinoma
Ductal carcinoma in situ, comedo type
Sclerosing adenosis
Fat necrosis
Show answer and explanation
Correct answer: C. Ductal carcinoma in situ, comedo type
Clustered, fine, linear and branching microcalcifications on screening mammography in a woman with no mass are the typical presentation of ductal carcinoma in situ. The biopsy shows a malignant proliferation of high-grade, pleomorphic cells that fills and distends ducts. The central necrosis with dystrophic calcification defines the comedo subtype (on cut section, the necrotic cores can be expressed like comedones), and the calcified necrotic debris casts the branching duct pattern seen on mammography. The intact myoepithelial layer and basement membrane around every duct (shown here by continuous p63 staining) and the absence of stromal tumor cells mean the lesion is still in situ. DCIS is a direct precursor of invasive ductal carcinoma, and high-grade comedo lesions carry the highest risk of progression.
A. Lobular carcinoma in situ is usually an incidental finding without calcifications; its cells are small, uniform and discohesive and lack E-cadherin, unlike these pleomorphic cohesive cells with necrosis. B. Invasive ductal carcinoma requires tumor cells beyond the myoepithelial layer and basement membrane in the stroma, which is absent here. D. Sclerosing adenosis produces calcifications that can mimic carcinoma, but it consists of benign, compressed small glands with preserved myoepithelium and no atypia or necrosis. E. Fat necrosis can calcify but shows necrotic fat and foamy macrophages rather than malignant ductal cells.
Educational objective: The key takeaway is that comedo DCIS is a high-grade malignant ductal proliferation with central necrosis that calcifies into branching mammographic microcalcifications, confined by an intact myoepithelial layer and basement membrane.
In situ carcinoma stays inside the myoepithelial layer and basement membrane; invasive carcinoma breaks through. Lobular lesions lose E-cadherin, so their cells are discohesive and invade in single file.
A 19-year-old man is evaluated for episodic headaches, palpitations, and sweating. He is tall and thin with long limbs, and he has small nodules on the lips and the anterior tongue. Blood pressure is 176/104 mm Hg. Plasma free metanephrines and serum calcitonin are markedly elevated, and a firm thyroid nodule is palpable. Serum calcium and PTH are normal. Biopsies of the oral nodules show tangled nerve fibers. His father had a thyroid cancer removed at age 25.
Which of the following best describes the inherited mutation responsible for this condition?
Loss-of-function mutation in a nuclear scaffold protein
Loss-of-function mutation in a RAS GTPase-activating protein
Loss-of-function mutation in an E3 ubiquitin ligase subunit
Amplification of a nuclear transcription factor gene
Gain-of-function mutation in a receptor tyrosine kinase
Show answer and explanation
Correct answer: E. Gain-of-function mutation in a receptor tyrosine kinase
Pheochromocytoma (episodic hypertension, high metanephrines), medullary thyroid carcinoma (high calcitonin from parafollicular C cells), mucosal neuromas of the lips and tongue, and a marfanoid habitus without hyperparathyroidism define MEN 2B. It is caused by a germline activating mutation of RET, a receptor tyrosine kinase that signals through the RAS and MAP kinase pathway. This is unusual among familial cancer syndromes, most of which are caused by inherited tumor suppressors that need a second hit. Because RET is an oncogene, one mutated allele is enough to drive C-cell and chromaffin cell proliferation, and penetrance of medullary thyroid carcinoma is nearly complete, so carriers undergo prophylactic thyroidectomy, in MEN 2B within the first year of life. The same gene causes MEN 2A and familial medullary thyroid carcinoma, and somatic RET rearrangements occur in papillary thyroid carcinoma.
A. Loss of menin, a nuclear scaffold protein, causes MEN 1 (parathyroid, pituitary, and pancreatic tumors). B. Loss of neurofibromin, a RAS-GAP, causes neurofibromatosis type 1, which can include pheochromocytoma but not medullary thyroid carcinoma or mucosal neuromas. C. Loss of VHL, a substrate-recognition subunit of an E3 ligase, causes pheochromocytoma with renal cell carcinoma and hemangioblastoma. D. Gene amplification, such as N-MYC in neuroblastoma, is a somatic event and is not inherited.
Educational objective: The key takeaway is that MEN 2A and 2B result from inherited gain-of-function mutations of the RET receptor tyrosine kinase, an oncogene, so one mutant allele suffices.
Oncogenes sit at every level of the growth relay (membrane receptors, the RAS switch and its kinases, cytoplasmic fusion kinases, nuclear MYC and cyclin D1), plus BCL-2, which blocks apoptosis rather than driving growth.